0.01q^2+0.30q-105.91=0

Solution for 0.01q^2+0.30q-105.91=0 equation:

0.01q^2+0.30q-105.91=0

a = 0.01; b = 0.30; c = -105.91;
Δ = b2-4ac
Δ = 0.302-4·0.01·(-105.91)
Δ = 4.3264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.30)-\sqrt{4.3264}}{2*0.01}=\frac{-0.3-\sqrt{4.3264}}{0.02}
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.30)+\sqrt{4.3264}}{2*0.01}=\frac{-0.3+\sqrt{4.3264}}{0.02}
$